A subshell with n=3 and l=2 can accommodate a | vedclass

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(A) The azimuthal quantum number $(l)$ determines the subshell type. For a given subshell,the number of orbitals is given by $(2l + 1)$.Each orbital c

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$10$ electrons

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(A) The azimuthal quantum number $(l)$ determines the subshell type. For a given subshell,the number of orbitals is given by $(2l + 1)$.Each orbital can hold a maximum of $2$ electrons.Therefore,the maximum number of electrons in a subshell is $2 	imes (2l + 1)$.Given $n=3$ and $l=2$,this corresponds to the $3d$ subshell.Substituting $l=2$ into the formula: $2 	imes (2(2) + 1) = 2 	imes (4 + 1) = 2 	imes 5 = 10$ electrons.Thus,the $3d$ subshell can accommodate a maximum of $10$ electrons.

$A$ subshell with $n=3$ and $l=2$ can accommodate a maximum of:

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