left[ML^2 T^{-2} K^{-1}right] is the dimensio | vedclass

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(A) The $SI$ unit of the Boltzmann constant $(k_B)$ is Joule per Kelvin $(J/K)$.Energy $(J)$ has the dimensional formula $\left[ML^2 T^{-2}\right]$.Te

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Boltzmann constant

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(A) The $SI$ unit of the Boltzmann constant $(k_B)$ is Joule per Kelvin $(J/K)$.Energy $(J)$ has the dimensional formula $\left[ML^2 T^{-2}\right]$.Temperature $(K)$ has the dimensional formula $\left[K^1\right]$.Therefore,the dimensional formula for the Boltzmann constant is $\left[ML^2 T^{-2}\right] / \left[K^1\right] = \left[ML^2 T^{-2} K^{-1}\right]$.

$\left[ML^2 T^{-2} K^{-1}\right]$ is the dimensional formula of which physical quantity?

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