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(C) Given that atomic mass $= 1 	ext{ amu} = 1.66 	imes 10^{-27} 	ext{ kg}$.By using Einstein's mass-energy equivalence relation,$E = mc^2$,where $

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$931 	ext{ MeV}$

Vedclass · Answer

(C) Given that atomic mass $= 1 	ext{ amu} = 1.66 	imes 10^{-27} 	ext{ kg}$.By using Einstein's mass-energy equivalence relation,$E = mc^2$,where $c = 3 	imes 10^8 	ext{ m/s}$ is the speed of light.$E = (1.66 	imes 10^{-27} 	ext{ kg}) 	imes (3 	imes 10^8 	ext{ m/s})^2 = 1.494 	imes 10^{-11} 	ext{ J}$.We know that $1 	ext{ MeV} = 1.602 	imes 10^{-13} 	ext{ J}$.Therefore,$E = \frac{1.494 	imes 10^{-11} 	ext{ J}}{1.602 	imes 10^{-13} 	ext{ J/MeV}} \approx 931 	ext{ MeV}$.Thus,$1 	ext{ amu}$ is equivalent to $931 	ext{ MeV}$ of energy.

$1 \text{ amu}$ is equal to

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