$A$ $10 \mu F$ capacitor is charged by a $100 \text{ V}$ battery. It is disconnected from the battery and is connected to another uncharged capacitor of capacitance $30 \mu F$. During this process,the electrostatic energy lost by the first capacitor is

  • A
    $5 \times 10^{-2} \text{ J}$
  • B
    $1.25 \times 10^{-2} \text{ J}$
  • C
    $2.75 \times 10^{-2} \text{ J}$
  • D
    $3.75 \times 10^{-2} \text{ J}$

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