A bomb moving with velocity (40 hat{i} + 50 h | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the mass of the smaller piece be $m$ and the mass of the larger piece be $4m$. The total mass is $5m$.According to the law of conservation of

Vedclass · Accepted Answer

$45 \hat{j} - 35 \hat{k}$

Vedclass · Answer

(A) Let the mass of the smaller piece be $m$ and the mass of the larger piece be $4m$. The total mass is $5m$.According to the law of conservation of linear momentum,the initial momentum equals the final momentum:$P_{initial} = P_{final}$$5m(40 \hat{i} + 50 \hat{j} - 25 \hat{k}) = m(200 \hat{i} + 70 \hat{j} + 15 \hat{k}) + 4m(\vec{v}_{large})$Dividing by $m$:$5(40 \hat{i} + 50 \hat{j} - 25 \hat{k}) = (200 \hat{i} + 70 \hat{j} + 15 \hat{k}) + 4\vec{v}_{large}$$(200 \hat{i} + 250 \hat{j} - 125 \hat{k}) - (200 \hat{i} + 70 \hat{j} + 15 \hat{k}) = 4\vec{v}_{large}$$0 \hat{i} + 180 \hat{j} - 140 \hat{k} = 4\vec{v}_{large}$$\vec{v}_{large} = \frac{180 \hat{j} - 140 \hat{k}}{4} = 45 \hat{j} - 35 \hat{k} 	ext{ m/s}$.

Similar Questions

In the following common emitter circuit,if $\beta = 100$,$V_{CE} = 7 \, V$,$V_{BE} = \text{Negligible}$,and $R_C = 2 \, k\Omega$,then find $I_B$ in $mA$.

In a triangle,if $b=20, c=21$ and $\sin A=\frac{3}{5}$,then $a$ is equal to :

The point collinear with $(1, -2, -3)$ and $(2, 0, 0)$ among the following is

In the following combinations of logic gates,the outputs of $A, B$ and $C$ are respectively:

Vedclass Test Series

Exam Paper Generator

Online Exam Module