A TV transmission antenna is 40 m tall. How | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The range $(d)$ of a $TV$ transmission antenna of height $h$ is given by the formula: $d = \sqrt{2hR}$,where $R$ is the radius of the Earth.Given:

Vedclass · Accepted Answer

$512 \pi 	imes 10^6 \ m^2$

Vedclass · Answer

(B) The range $(d)$ of a $TV$ transmission antenna of height $h$ is given by the formula: $d = \sqrt{2hR}$,where $R$ is the radius of the Earth.Given: $h = 40 \ m$ and $R = 6400 \ km = 6400 	imes 10^3 \ m$.The service area covered by the antenna is the area of a circle with radius $d$,given by: $Area = \pi d^2$.Substituting the value of $d^2 = 2hR$ into the area formula:$Area = \pi (2hR)$$Area = \pi 	imes 2 	imes 40 	imes (6400 	imes 10^3)$$Area = \pi 	imes 80 	imes 6400 	imes 10^3$$Area = 512000 	imes 10^3 \pi \ m^2$$Area = 512 	imes 10^6 \pi \ m^2$.

$A$ $TV$ transmission antenna is $40 \ m$ tall. How much service area can it cover if the receiving antenna is at the ground level? (Radius of the Earth $= 6400 \ km$)

Similar Questions

$A$ diode detector is used to detect an amplitude modulated wave with $60\%$ modulation,using a capacitor of $250 \ pF$ in parallel with a resistor of $100 \ k\Omega$. What is the maximum modulation frequency that can be detected by this circuit?

For a television network,$5 \times 10^5$ channels are granted. If the central frequency of the microwave link is $25 \text{ GHz}$ and the allotted bandwidth for each channel is $2 \text{ kHz}$,then what percentage of the link is used for the network (in $\%$)?

The electron density of $E, F_1, F_2$ layers of the ionosphere is $2 \times 10^{11} \, m^{-3}$,$5 \times 10^{11} \, m^{-3}$,and $8 \times 10^{11} \, m^{-3}$ respectively. What is the ratio of critical frequencies for the reflection of radio waves?

For effective transmission of a wave with frequency $3000 \text{ kHz}$,the minimum length of the antenna should be ...... $m$.

If a message signal of frequency $10 kHz$ and peak voltage $12 V$ is used to modulate a carrier wave of frequency $1 MHz$, the modulation index is $0.6$. To make the modulation index $0.75$, the carrier peak voltage should be

Vedclass Test Series

Exam Paper Generator

Online Exam Module