A TV transmission tower of height h covers a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The range $d$ of a $TV$ transmission tower of height $h$ is given by the formula $d = \sqrt{2hR}$,where $R$ is the radius of the Earth.Initially,$

Vedclass · Accepted Answer

$(\sqrt{3/2}-1) d$

Vedclass · Answer

(B) The range $d$ of a $TV$ transmission tower of height $h$ is given by the formula $d = \sqrt{2hR}$,where $R$ is the radius of the Earth.Initially,$d = \sqrt{2hR}$.When the height is increased to $h' = 3/2 h$,the new range $d'$ becomes:$d' = \sqrt{2h'R} = \sqrt{2(3/2 h)R} = \sqrt{3/2} \sqrt{2hR} = \sqrt{3/2} d$.The change in range is $\Delta d = d' - d$.Substituting the values,we get $\Delta d = \sqrt{3/2} d - d = (\sqrt{3/2} - 1) d$.

$A$ $TV$ transmission tower of height $h$ covers a range of distance $d$. By how much will the range change if the height is increased to $3/2 h$?

Similar Questions

The maximum range $(R_{max})$ of a radar is proportional to:

What is a transducer?

By what percentage will the transmission range of a $TV$ tower be affected when the height of the tower is increased by $21 \%$ (in $\%$)?

$A$ transmitting antenna at the top of a tower has height $32\, m$ and the height of the receiving antenna is $50\, m$. What is the maximum distance between them for satisfactory communication in line of sight $(LOS)$ mode? ........$km$

The bit rate for a signal,which has a sampling rate of $8 \, kHz$ and where $16$ quantisation levels have been used,is ......... $bits/sec$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module