A complex compound of Co^{3+} with molecular | vedclass

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(B) The central metal ion is $Co^{3+}$ and the coordination number of $Co^{3+}$ is typically $6$. The molecular formula is $CoCl_3 \cdot yNH_3$ becaus

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(B) The central metal ion is $Co^{3+}$ and the coordination number of $Co^{3+}$ is typically $6$. The molecular formula is $CoCl_3 \cdot yNH_3$ because $Co$ is in the $+3$ oxidation state.When the complex dissolves in water,it produces $3$ ions. This implies the ionization sphere contains $2$ chloride ions,represented as $[CoCl(NH_3)_5]Cl_2$.The dissociation is: $[CoCl(NH_3)_5]Cl_2 \rightleftharpoons [CoCl(NH_3)_5]^{2+} + 2Cl^-$.In this structure,the $Cl^-$ ion inside the coordination sphere acts as a ligand (satisfying secondary valency) and also balances the charge of the metal (satisfying primary valency).Thus,only $1$ $Cl^-$ ion satisfies both primary and secondary valencies.

$A$ complex compound of $Co^{3+}$ with molecular formula $CoCl_{x} \cdot yNH_3$ gives a total of $3$ ions when dissolved in water. How many $Cl^{-}$ ions satisfy both primary and secondary valencies in this complex?

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