$A$ circuit is shown in the figure for which $C_1=(3 \pm 0.011) \mu F$,$C_2=(5 \pm 0.01) \mu F$,and $C_3=(1 \pm 0.01) \mu F$. If $C$ is the equivalent capacitance across $AB$,then $C$ is given by:

  • A
    $(0.9 \pm 0.114) \mu F$
  • B
    $(0.9 \pm 0.01) \mu F$
  • C
    $(0.9 \pm 0.023) \mu F$
  • D
    $(0.9 \pm 0.09) \mu F$

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