(B) The galvanic cell can be represented as: $Mg | Mg^{2+} || Cu^{2+} | Cu$. The standard cell potential is given by the formula: $E^{\circ}_{cell} =

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(B) The galvanic cell can be represented as: $Mg | Mg^{2+} || Cu^{2+} | Cu$. The standard cell potential is given by the formula: $E^{\circ}_{cell} = E^{\circ}_{cathode} - E^{\circ}_{anode}$. Here,$E^{\circ}_{cathode} = E^{\circ}_{Cu^{2+}/Cu} = 0.34 \ V$ and $E^{\circ}_{cell} = 2.71 \ V$. Substituting these values: $2.71 \ V = 0.34 \ V - E^{\circ}_{Mg^{2+}/Mg}$. Therefore,$E^{\circ}_{Mg^{2+}/Mg} = 0.34 \ V - 2.71 \ V = -2.37 \ V$.

Class 12 Chemistry Electrochemistry Electrode potential and ECell

Easy

$Mg^{2+}$ displaces hydrogen from acids but copper does not. $A$ galvanic cell prepared by combining $Cu/Cu^{2+}$ and $Mg/Mg^{2+}$ has an $EMF$ of $2.71 \ V$ at $298 \ K$. If the potential of copper electrode is $0.34 \ V$,what is the reduction potential of $Mg$ electrode?

TS EAMCET 2020 All TS EAMCET

A
$+3.05 \ V$
B
$-2.37 \ V$
C
$+2.37 \ V$
D
$2 \ V$

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Electrochemistry

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Electrode potential and ECell

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$Mg^{2+}$ displaces hydrogen from acids but copper does not. $A$ galvanic cell prepared by combining $Cu/Cu^{2+}$ and $Mg/Mg^{2+}$ has an $EMF$ of $2.71 \ V$ at $298 \ K$. If the potential of copper electrode is $0.34 \ V$,what is the reduction potential of $Mg$ electrode?

Similar Questions

Which of the following metals will not evolve $H_2$ gas from dilute $H_2SO_4$ solution?

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For the cell reaction,$2Ce^{4+} + Co \to 2Ce^{3+} + Co^{2+}$,$E_{cell}^o$ is $1.89 \, V$ and $E_{Co/Co^{2+}}^o = +0.28 \, V$. If $E_{Ce^{4+}/Ce^{3+}}^o = x$,then $x$ is ............. $V$.

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The standard electrode potential for the two electrodes $A^{+}/A$ and $B^{+}/B$ are respectively $0.5 \ V$ and $0.75 \ V$. The $EMF$ of the given cell $A | A^{+}(a = 1) || B^{+}(a = 1) | B$ will be $.......... \ V$. (in $.25$)

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