frac{1-cos 2 theta+sin 2 theta}{1+cos 2 theta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) We use the trigonometric identities: $\cos 2 	heta = 1 - 2 \sin^2 	heta = 2 \cos^2 	heta - 1$ and $\sin 2 	heta = 2 \sin 	heta \cos 	heta$.S

Vedclass · Accepted Answer

$	an 	heta$

Vedclass · Answer

(C) We use the trigonometric identities: $\cos 2 	heta = 1 - 2 \sin^2 	heta = 2 \cos^2 	heta - 1$ and $\sin 2 	heta = 2 \sin 	heta \cos 	heta$.Substituting these into the expression:$\frac{1 - (1 - 2 \sin^2 	heta) + 2 \sin 	heta \cos 	heta}{1 + (2 \cos^2 	heta - 1) + 2 \sin 	heta \cos 	heta}$$= \frac{2 \sin^2 	heta + 2 \sin 	heta \cos 	heta}{2 \cos^2 	heta + 2 \sin 	heta \cos 	heta}$$= \frac{2 \sin 	heta (\sin 	heta + \cos 	heta)}{2 \cos 	heta (\cos 	heta + \sin 	heta)}$$= \frac{\sin 	heta}{\cos 	heta} = 	an 	heta$.

$\frac{1-\cos 2 \theta+\sin 2 \theta}{1+\cos 2 \theta+\sin 2 \theta}=$

Similar Questions

$\sqrt{2 + \sqrt{2 + 2\cos 4\theta}} = $

If $x = \log_e \left[ \cot \left( \frac{\pi}{4} + \theta \right) \right]$ where $|\theta| < \frac{\pi}{4}$,then $\sinh x =$

If $\sin t + \cos t = \frac{1}{5}$,then $\tan \frac{t}{2}$ is equal to:

Find $\sin \frac{x}{2}, \cos \frac{x}{2}$ and $\tan \frac{x}{2}$ given that $\cos x = -\frac{1}{3}$ and $x$ is in quadrant $III$.

If $\cos A = \frac{3}{4}$,then $32\sin \frac{A}{2}\cos \frac{5A}{2} = $

Vedclass Test Series

Exam Paper Generator

Online Exam Module