CH_3-CH_2-Br + Nu^{Theta} rightarrow CH_3-CH_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The rate of nucleophilic substitution reaction depends on the nucleophilicity of the nucleophile $Nu^{\Theta}$. Stronger nucleophiles react faster

Vedclass · Accepted Answer

$IV > III > I > II$

Vedclass · Answer

(A) The rate of nucleophilic substitution reaction depends on the nucleophilicity of the nucleophile $Nu^{\Theta}$. Stronger nucleophiles react faster. Comparing the basicity and nucleophilicity: $CH_3O^{\Theta}$ is a stronger base and nucleophile than $OH^{\Theta}$ due to the $+I$ effect of the $CH_3$ group. $OH^{\Theta}$ is a stronger nucleophile than $PhO^{\Theta}$ because the negative charge in $PhO^{\Theta}$ is delocalized over the benzene ring. $PhO^{\Theta}$ is a stronger nucleophile than $CH_3COO^{\Theta}$ because the negative charge in $CH_3COO^{\Theta}$ is delocalized over two oxygen atoms. Thus,the order of nucleophilicity is $(IV) CH_3O^{\Theta} > (III) OH^{\Theta} > (I) PhO^{\Theta} > (II) CH_3COO^{\Theta}$.

$CH_3-CH_2-Br + Nu^{\Theta} \rightarrow CH_3-CH_2-Nu + Br^{\Theta}$
The decreasing order of the reaction rate with nucleophile $Nu^{\Theta}$ is $Nu^{\Theta} = (I) PhO^{\Theta}; (II) CH_3COO^{\Theta}; (III) OH^{\Theta}; (IV) CH_3O^{\Theta}$

Similar Questions

Benzene $\xrightarrow[{Anhy. AlCl_3}]{{CH_3Cl}} A \,$ $\xrightarrow[{hv}]{{Cl_2 (1 \, mole)}} B$ $\xrightarrow{{AgCN}} C$
Which is correct for the above reaction?

$A$ dihaloalkane '$X$',having formula $C_{3}H_{6}Cl_{2}$,on hydrolysis gives a compound that can reduce Tollen's reagent. The compound '$X$' is

When chloroform is treated with conc. $HNO_3$,it gives:

What is the product formed when chloroform reacts with zinc dust in the presence of water?

$C_2H_5Br$ $\xrightarrow{KCN} A$ $\xrightarrow{\text{Hydrolysis}} B$
The compound $A$ in the above reaction is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$CH_3-CH_2-Br + Nu^{\Theta} \rightarrow CH_3-CH_2-Nu + Br^{\Theta}$ The decreasing order of the reaction rate with nucleophile $Nu^{\Theta}$ is $Nu^{\Theta} = (I) PhO^{\Theta}; (II) CH_3COO^{\Theta}; (III) OH^{\Theta}; (IV) CH_3O^{\Theta}$