$CaC_2 + 2D_2O \longrightarrow$ "$P$" $+ Ca(OD)_2$
In the above reaction,the product "$P$" is:
In the above reaction,the product "$P$" is:
- A$C_2H_2$
- B$C_2H_4$
- C$CD_4$
- D$C_2D_2$
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