$A$ and $B$ are two events of a random experiment such that $P(B)=0.4$, $P(A \cap \bar{B})=0.5$, and $P(A \cup B) + P\left(\frac{B}{A \cup \bar{B}}\right) = 1.15$. Then $P(A) = $

  • A
    $0.9$
  • B
    $0.8$
  • C
    $0.7$
  • D
    $0.25$

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