(A) Let $N$ be the number appearing on the die. The possible values for $N$ are $\{1, 2, 3, 4, 5, 6\}$.If $N$ is even $(N \in \{2, 4, 6\})$, the numbe

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) Let $N$ be the number appearing on the die. The possible values for $N$ are $\{1, 2, 3, 4, 5, 6\}$.If $N$ is even $(N \in \{2, 4, 6\})$, the number of chocolates $X = N + 2$.For $N = 2$, $X = 2 + 2 = 4$.For $N = 4$, $X = 4 + 2 = 6$.For $N = 6$, $X = 6 + 2 = 8$.If $N$ is odd $(N \in \{1, 3, 5\})$, the number of chocolates $X = N + 3$.For $N = 1$, $X = 1 + 3 = 4$.For $N = 3$, $X = 3 + 3 = 6$.For $N = 5$, $X = 5 + 3 = 8$.Thus, the set of all possible values of $X$ is $\{4, 6, 8\}$.Therefore, the range of $X$ is $\{4, 6, 8\}$.

Class 12 Mathematics Probability Probability distribution

Easy

$A$ boy rolls a die once. If an even number appears, the number of chocolates the boy gets is equal to two more than the number that appeared. If an odd number appears on the die, the number of chocolates he gets is equal to three more than the number that appeared. If a random variable $X$ represents the number of chocolates the boy receives, then the range of $X$ is:

TS EAMCET 2019 All TS EAMCET

A
$\{4, 6, 8\}$
B
$\{3, 5, 7\}$
C
$\{3, 4, 7\}$
D
$\{2, 3\}$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Mathematics Questions

Chapter

Probability

Subtopic

Probability distribution

Previous Year

TS EAMCET 2019 Paper All TS EAMCET years →

Let $X$ be a random variable such that the probability function of a distribution is given by $P(X=0) = \frac{1}{2}$ and $P(X=j) = \frac{1}{3^j}$ for $j = 1, 2, 3, \ldots, \infty$. Then the mean of the distribution and $P(X \text{ is positive and even})$ respectively are:

MediumJEE MAIN 2021

View Solution

The value of the constant $c$,so that $P(x)=c\left(\frac{2}{3}\right)^{x}$,$x=1,2,3, \ldots$ is the probability distribution function of a discrete random variable $X$ is

MediumAP EAMCET 2023

View Solution

Let a pair of dice be thrown and the random variable $X$ be the sum of the numbers that appear on the two dice. Find the mean or expectation of $X$.

Difficult

View Solution

If $X$ is a Poisson variate with $P(X=0)=0.8$,then the variance of $X$ is

DifficultAP EAMCET 2004

View Solution

Two dice are rolled. If a random variable $X$ denotes the sum of the numbers on them and $\mu$ denotes the mean of $X$, then $\mu+P(X < 5)+P(X>9)+P(X=7)=$

MediumTS EAMCET 2019

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Similar Questions

Let $X$ be a random variable such that the probability function of a distribution is given by $P(X=0) = \frac{1}{2}$ and $P(X=j) = \frac{1}{3^j}$ for $j = 1, 2, 3, \ldots, \infty$. Then the mean of the distribution and $P(X \text{ is positive and even})$ respectively are:

The value of the constant $c$,so that $P(x)=c\left(\frac{2}{3}\right)^{x}$,$x=1,2,3, \ldots$ is the probability distribution function of a discrete random variable $X$ is

Let a pair of dice be thrown and the random variable $X$ be the sum of the numbers that appear on the two dice. Find the mean or expectation of $X$.

If $X$ is a Poisson variate with $P(X=0)=0.8$,then the variance of $X$ is

Two dice are rolled. If a random variable $X$ denotes the sum of the numbers on them and $\mu$ denotes the mean of $X$, then $\mu+P(X < 5)+P(X>9)+P(X=7)=$

Vedclass Test Series

Exam Paper Generator

Online Exam Module