A coin is tossed n times. The probability of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The probability of getting a head in a single toss is $p = \frac{1}{2}$, and the probability of getting a tail is $q = 1 - p = \frac{1}{2}$.The pr

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) The probability of getting a head in a single toss is $p = \frac{1}{2}$, and the probability of getting a tail is $q = 1 - p = \frac{1}{2}$.The probability of getting no heads in $n$ tosses is $P(	ext{no heads}) = q^n = (\frac{1}{2})^n$.The probability of getting at least one head is $P(	ext{at least one head}) = 1 - P(	ext{no heads}) = 1 - (\frac{1}{2})^n$.Given that $1 - (\frac{1}{2})^n > 0.8$, we have:$1 - 0.8 > (\frac{1}{2})^n$$0.2 > (\frac{1}{2})^n$$\frac{1}{5} > \frac{1}{2^n}$$2^n > 5$.For $n = 2$, $2^2 = 4 For $n = 3$, $2^3 = 8 > 5$.Thus, the least value of $n$ is $3$.

$A$ coin is tossed $n$ times. The probability of getting a head at least once is greater than $0.8$. Then, the least value of such $n$ is:

Similar Questions

On average, one out of $10$ persons is busy. If $6$ persons are selected at random, then the probability that at least $5$ of them will be busy is...

In a Binomial distribution,if $n$ is the number of trials and the mean and variance are $4$ and $3$ respectively,then $2^{32} P\left(X=\frac{n}{2}\right)=$

Ten bulbs are drawn successively,with replacement,from a lot containing $10 \%$ defective bulbs. The probability that there is at least one defective bulb is:

$A$ fair coin is tossed a fixed number of times. If the probability of getting exactly $3$ heads equals the probability of getting exactly $5$ heads, then the probability of getting exactly one head is

The probability distribution of the number of doublets in four throws of a pair of dice is given by

Vedclass Test Series

Exam Paper Generator

Online Exam Module