A body of mass 1 kg is executing simple harm | vedclass

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(B) Given: Mass $m = 1 \ kg$, displacement $y = 6 \sin (100 t + \pi/4) \ cm$.Comparing with the general equation $y = A \sin (\omega t + \phi)$, we ge

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$18$

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(B) Given: Mass $m = 1 \ kg$, displacement $y = 6 \sin (100 t + \pi/4) \ cm$.Comparing with the general equation $y = A \sin (\omega t + \phi)$, we get amplitude $A = 6 \ cm = 0.06 \ m$ and angular frequency $\omega = 100 \ rad/s$.The maximum kinetic energy $(K_{max})$ of a particle in $SHM$ is given by the formula $K_{max} = \frac{1}{2} m \omega^2 A^2$.Substituting the values: $K_{max} = \frac{1}{2} 	imes 1 	imes (100)^2 	imes (0.06)^2$.$K_{max} = \frac{1}{2} 	imes 10000 	imes 0.0036$.$K_{max} = 5000 	imes 0.0036 = 18 \ J$.

$A$ body of mass $1 \ kg$ is executing simple harmonic motion $(SHM)$. Its displacement $y$ (in $cm$) at time $t$ is given by $y = 6 \sin (100 t + \pi/4) \ cm$. Its maximum kinetic energy is (in $J$)

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