A body is falling freely from a point A at a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let the velocity of the particle at point $B$ be $v$. Since the body is falling freely, the acceleration is $g$. For the interval $BC$, the time t

Vedclass · Accepted Answer

$0.5$

Vedclass · Answer

(B) Let the velocity of the particle at point $B$ be $v$. Since the body is falling freely, the acceleration is $g$. For the interval $BC$, the time taken is $t_1 = 2 \ s$. Using the equation of motion $s = ut + \frac{1}{2}at^2$: $BC = v(2) + \frac{1}{2}g(2)^2 = 2v + 2g$  --- $(i)$ For the interval $BD$, the total time is $t_2 = 2 + 1 = 3 \ s$. $BD = BC + CD = 2BC$ (since $BC = CD$). $BD = v(3) + \frac{1}{2}g(3)^2 = 3v + 4.5g$ Since $BD = 2BC$, we have: $2(2v + 2g) = 3v + 4.5g$ $4v + 4g = 3v + 4.5g$ $v = 0.5g$ Now, for the interval $AB$, let the time taken be $t$. Since the body falls freely from $A$, its initial velocity $u = 0$. $v = u + at \Rightarrow 0.5g = 0 + gt$ $t = 0.5 \ s$.

Similar Questions

$A$ ball is thrown upwards. It takes $4 \, s$ to reach back to the ground. Its initial velocity is........$m/s$.

$A$ ball is thrown vertically upwards from the top of a tower with a velocity $u$. This ball reaches the ground level with a velocity $4u$. The height of the tower is:

$A$ ball is dropped downwards. After $1$ second,another ball is dropped downwards from the same point. What is the distance between them after $3$ seconds?

$A$ ball of mass $0.5 \; kg$ is dropped from a height of $10 \; m$. The height from the ground,at which the magnitude of velocity becomes equal to the magnitude of acceleration due to gravity,is $\dots \; m$. (Use $g = 10 \; m/s^2$).

Vedclass Test Series

Exam Paper Generator

Online Exam Module