$A$ particle is projected with velocity $2 \sqrt{gh}$ at an angle $60^{\circ}$ to the horizontal so that it just clears two walls of equal height $h$ which are at a distance $2h$ from each other. The time taken by the particle to travel between these two walls is
- A$2 \sqrt{\frac{2h}{g}}$
- B$\sqrt{\frac{h}{2g}}$
- C$2 \sqrt{\frac{h}{g}}$
- D$\sqrt{\frac{h}{g}}$
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