A point object O is placed on the axis of a c | vedclass

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(A) For refraction at a spherical surface, the formula is given by:$\frac{\mu_2}{v} - \frac{\mu_1}{u} = \frac{\mu_2 - \mu_1}{R}$Here, the light travel

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$4$

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(A) For refraction at a spherical surface, the formula is given by:$\frac{\mu_2}{v} - \frac{\mu_1}{u} = \frac{\mu_2 - \mu_1}{R}$Here, the light travels from the glass $(\mu_1 = 1.6)$ to the air $(\mu_2 = 1)$.The image is formed at $v = -5 \,mm$ (since it is a virtual image formed on the same side as the object, relative to the direction of light).The radius of curvature $R = -3 \,mm$ (following sign convention, as the center of curvature is to the left of the surface).Substituting these values into the formula:$\frac{1}{-5} - \frac{1.6}{u} = \frac{1 - 1.6}{-3}$$-0.2 - \frac{1.6}{u} = \frac{-0.6}{-3}$$-0.2 - \frac{1.6}{u} = 0.2$$-\frac{1.6}{u} = 0.4$$u = -\frac{1.6}{0.4} = -4 \,mm$The distance of the object from the surface is $4 \,mm$.

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