$A$ transistor having a $\beta$ equal to $80$ has a change in base current of $250 \mu A$. What is the change in collector current?

$A$ common emitter amplifier is designed with an $NPN$ transistor $(\alpha = 0.99)$. The input impedance is $1 \ k\Omega$ and the load resistance is $10 \ k\Omega$. The voltage gain will be:

For a transistor,$\beta = 100$. The value of $\alpha$ is

$A$ transistor is operated in $CE$ configuration at $V_{CC} = 2 \ V$ such that a change in base current from $100 \ \mu A$ to $200 \ \mu A$ produces a change in the collector current from $9 \ mA$ to $16.5 \ mA$. The value of current gain,$\beta$ is .........

In a $CE$ transistor amplifier,there is a current and voltage gain associated with the circuit. In other words,there is a power gain. Considering power as a measure of energy,does the circuit violate the law of conservation of energy?

In an $n-p-n$ transistor,$10^{8}$ electrons enter the emitter in $10^{-8} \,s$. If $1\%$ of electrons are lost in the base,the fraction of current that enters the collector and the current amplification factor $\beta$ are respectively: