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(C) The modulation index $\mu$ is defined as the ratio of the peak voltage of the modulating signal $(A_m)$ to the peak voltage of the carrier wave $(

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$12$

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(C) The modulation index $\mu$ is defined as the ratio of the peak voltage of the modulating signal $(A_m)$ to the peak voltage of the carrier wave $(A_c)$.$\mu = \frac{A_m}{A_c}$Given, modulation index $\mu = 60 \% = 0.6$ and carrier peak voltage $A_c = 20 V$.Substituting the values in the formula:$0.6 = \frac{A_m}{20}$$A_m = 0.6 	imes 20 = 12 V$Therefore, the peak voltage of the modulating signal is $12 V$.

$A$ carrier wave of peak voltage $20 V$ is used to transmit a message signal. For getting a modulation index of $60 \%$, the peak voltage of the modulating signal is (in $V$)

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