x grams of water is mixed in 69 g of ethanol | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let $w_A$ be the mass of water $(H_2O)$ and $w_B$ be the mass of ethanol $(C_2H_5OH)$.Given: $w_B = 69 \ g$, molar mass of ethanol $(m_B)$ = $46 \

Vedclass · Accepted Answer

$18$

Vedclass · Answer

(D) Let $w_A$ be the mass of water $(H_2O)$ and $w_B$ be the mass of ethanol $(C_2H_5OH)$.Given: $w_B = 69 \ g$, molar mass of ethanol $(m_B)$ = $46 \ g/mol$, molar mass of water $(m_A)$ = $18 \ g/mol$.Mole fraction of ethanol $(X_B)$ = $0.6$.Therefore, mole fraction of water $(X_A)$ = $1 - 0.6 = 0.4$.The formula for mole fraction is $X_B = \frac{n_B}{n_A + n_B}$, where $n$ is the number of moles.$n_B = \frac{69}{46} = 1.5 \ mol$.$n_A = \frac{x}{18} \ mol$.$0.6 = \frac{1.5}{\frac{x}{18} + 1.5}$.$0.6 	imes (\frac{x}{18} + 1.5) = 1.5$.$\frac{0.6x}{18} + 0.9 = 1.5$.$\frac{x}{30} = 0.6$.$x = 0.6 	imes 30 = 18 \ g$.

$x$ grams of water is mixed in $69 \ g$ of ethanol. The mole fraction of ethanol in the resultant solution is $0.6$. What is the value of $x$ in grams?

Similar Questions

The mole fraction of water in an $18 \% \, w/w$ aqueous solution of $C_6H_{12}O_6$ is .......

What is the molarity of acid in vinegar containing $4.0 \%$ acetic acid by $(w/w)$ and having a density of $1.02 \ g/mL$ (in $M$)?

What is the mass of glucose in $500 \ g$ of an aqueous solution of glucose having a molality of $0.5 \ m$?

If a solution is $98\% \ H_2SO_4$ by weight and has a density of $1.8 \ g/mL$,its molarity is ....... $M$.

The molarity of a solution obtained by mixing $750 \, mL$ of $0.5 \, M \, HCl$ with $250 \, mL$ of $2 \, M \, HCl$ will be $......... \, M$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module