4 moles of an ideal gas is at 0^circ C. At co | vedclass

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(B) According to Charles's Law,for a fixed amount of gas at constant pressure,the volume is directly proportional to the absolute temperature: $V \pro

Vedclass · Accepted Answer

$273$

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(B) According to Charles's Law,for a fixed amount of gas at constant pressure,the volume is directly proportional to the absolute temperature: $V \propto T$ or $\frac{V_1}{T_1} = \frac{V_2}{T_2}$.Given: Initial temperature $T_1 = 0^\circ C = 273 \ K$. Initial volume $V_1 = V$. Final volume $V_2 = 2V$.Substituting the values into the formula: $\frac{V}{273} = \frac{2V}{T_2}$.Solving for $T_2$: $T_2 = 2 	imes 273 = 546 \ K$.To convert the final temperature back to Celsius: $T_2(^\circ C) = 546 - 273 = 273^\circ C$.

$4$ moles of an ideal gas is at $0^\circ C$. At constant pressure,it is heated to double its volume. Its final temperature will be ...... $^\circ C$.

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