A polymer sample contains 3 molecules of mola | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The weight average molecular mass is calculated using the formula: $\bar{M}_w = \frac{\sum n_i M_i^2}{\sum n_i M_i}$ Given: $n_1 = 3, M_1 = 1000$

Vedclass · Accepted Answer

$737.7$

Vedclass · Answer

(B) The weight average molecular mass is calculated using the formula: $\bar{M}_w = \frac{\sum n_i M_i^2}{\sum n_i M_i}$ Given: $n_1 = 3, M_1 = 1000$ $n_2 = 3, M_2 = 500$ $n_3 = 4, M_3 = 200$ Numerator: $(3 	imes 1000^2) + (3 	imes 500^2) + (4 	imes 200^2) = 3,000,000 + 750,000 + 160,000 = 3,910,000$ Denominator: $(3 	imes 1000) + (3 	imes 500) + (4 	imes 200) = 3000 + 1500 + 800 = 5300$ $\bar{M}_w = \frac{3,910,000}{5300} \approx 737.7$

$A$ polymer sample contains $3$ molecules of molar mass $10^3$, $3$ molecules of molar mass $500$, and $4$ molecules of molar mass $200$. What is its weight average molecular mass?

Similar Questions

Which polymer is used in the manufacture of contact lenses for the eyes?

The $trans$-form of polyisoprene is:

Identify the addition polymer from the following:

What are the monomeric repeating units of Nylon-$6$ and Nylon-$6, 6$?

If $Cell-OH$ represents the formula of cellulose,identify the formula of cellulose xanthate from the following.

Vedclass Test Series

Exam Paper Generator

Online Exam Module