Fe(OH)_3 is a positively charged sol. For its | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $Fe(OH)_3$ is a positively charged sol. According to the Hardy-Schulze rule, the coagulating power of an electrolyte depends on the valency of the

Vedclass · Accepted Answer

$Na_3[Fe(CN)_6]$

Vedclass · Answer

(D) $Fe(OH)_3$ is a positively charged sol. According to the Hardy-Schulze rule, the coagulating power of an electrolyte depends on the valency of the ion carrying a charge opposite to that of the colloidal particles.Since $Fe(OH)_3$ is positively charged, it requires an anion for coagulation.The given electrolytes dissociate as follows:$Na_2SO_4 ightarrow 2Na^+ + SO_4^{2-}$$Na_3[Fe(CN)_6] ightarrow 3Na^+ + [Fe(CN)_6]^{3-}$$Cr(OH)_3$ and $Al(OH)_3$ are insoluble hydroxides and do not act as effective coagulating agents in this context.Comparing the valency of the anions, $[Fe(CN)_6]^{3-}$ has a valency of $3$, while $SO_4^{2-}$ has a valency of $2$.According to the Hardy-Schulze rule, the higher the valency of the coagulating ion, the greater is its coagulating power.Therefore, $[Fe(CN)_6]^{3-}$ is the most effective coagulating agent among the given options.Flocculation value = $\frac{1}{	ext{Coagulating power}}$. Since $[Fe(CN)_6]^{3-}$ has the highest coagulating power, it has the lowest flocculation value, making it the best precipitating agent.

$Fe(OH)_3$ is a positively charged sol. For its precipitation, the best precipitating agent is:

Similar Questions

Starch dispersed in hot water is an example of

Identify the correct statement regarding lyophilic colloids from the following.

Lyophobic colloids are:

The coagulating power of electrolytes having ions $Na^{+}$,$Ba^{2+}$ and $Al^{3+}$ for arsenic sulphide sol increases in the order:

Which of the following statements is/are not true?

Vedclass Test Series

Exam Paper Generator

Online Exam Module