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(C) For an isobaric process, the work done is given by $W = P \Delta V = n R \Delta T = 100 J$.For a monoatomic gas, the molar heat capacity at consta

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$250$

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(C) For an isobaric process, the work done is given by $W = P \Delta V = n R \Delta T = 100 J$.For a monoatomic gas, the molar heat capacity at constant pressure is $C_P = \frac{5}{2} R$.The heat supplied to the gas is given by $Q = n C_P \Delta T$.Substituting the value of $C_P$, we get $Q = n (\frac{5}{2} R) \Delta T = \frac{5}{2} (n R \Delta T)$.Since $n R \Delta T = 100 J$, we have $Q = \frac{5}{2} 	imes 100 J = 250 J$.

$A$ monoatomic gas does $100 J$ of work when it is expanded isobarically. How much heat is given to the gas in the process (in $J$)?

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