$A$ car travelling at a speed of $54 \ km/h$ towards a wall sounds a horn of frequency $400 \ Hz$. The difference in the frequencies of two sounds, one received directly from the car and the other reflected from the wall, noticed by a person standing between the car and the wall is (speed of sound in air is $335 \ m/s$):

  • A
    $35.9 \ Hz$
  • B
    $20 \ Hz$
  • C
    $70 \ Hz$
  • D
    $35.9 \ Hz$ (Wait, let's calculate: $v_s = 54 \ km/h = 15 \ m/s$, $v = 335 \ m/s$, $f = 400 \ Hz$. Direct sound frequency $f_1 = f = 400 \ Hz$. Reflected sound frequency $f_2 = f \times \frac{v}{v - v_s} = 400 \times \frac{335}{335 - 15} = 400 \times \frac{335}{320} = 418.75 \ Hz$. Difference $= 418.75 - 400 = 18.75 \ Hz$. Since $18.75 \ Hz$ is not in options, let's re-evaluate. If the observer is between the car and wall, the direct sound is $f_1 = f \times \frac{v}{v - v_s}$ and reflected is $f_2 = f \times \frac{v}{v - v_s}$. The difference is zero. Wait, the observer is stationary. Direct sound $f_1 = f \times \frac{v}{v - v_s}$. Reflected sound $f_2 = f \times \frac{v}{v - v_s}$. The difference is $0$. Let's re-read: 'person standing between the car and the wall'. The car is moving towards the wall. The person hears direct sound from the car (source moving towards observer) and reflected sound from the wall (wall acts as a source moving towards observer). Both frequencies are the same. Difference is Zero.

Explore More

Similar Questions

The frequency of sound heard by an observer moving towards a stationary source with certain speed is $n_1$ and if the observer moves away from the same source with same speed, the frequency of sound heard by the observer is $n_2$. If the speed of sound in air is $340 \ m/s$ and $n_1: n_2 = 71: 65$, then the speed of the observer is: (in $km/h$)

$A$ car $P$ travelling at $20\,ms^{-1}$ sounds its horn at a frequency of $400\,Hz$. Another car $Q$ is travelling behind the first car in the same direction with a velocity $40\,ms^{-1}$. The frequency heard by the passenger of the car $Q$ is approximately $.......\,Hz$. [Take,velocity of sound $= 360\,ms^{-1}$]

$A$ stationary source is emitting sound at a fixed frequency $f_0$,which is reflected by two cars approaching the source. The difference between the frequencies of sound reflected from the cars is $1.2\%$ of $f_0$. What is the difference in the speeds of the cars (in $km/h$) to the nearest integer? The cars are moving at constant speeds much smaller than the speed of sound,which is $330 \ m/s$.

Difficult
View Solution

When the observer moves towards a stationary source with velocity $V_{1}$,the apparent frequency of the emitted note is $F_{1}$. When the observer moves away from the source with velocity $V_{1}$,the apparent frequency is $F_{2}$. If $V$ is the velocity of sound in air and $F_{1} / F_{2} = 2$,then $V / V_{1}$ is equal to:

$A$ whistle revolves in a circle with an angular speed of $20 \; rad/s$ using a string of length $50 \; cm.$ If the frequency of sound from the whistle is $385 \; Hz,$ then what is the minimum frequency heard by an observer,who is far away from the centre in the same plane? $(v = 340 \; m/s)$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo