(B) Let $t_A = 2 \ s$ be the time interval for boy $A$ and $t_B = 1 \ s$ be the time interval for boy $B$.For a ball projected vertically, the time ta

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(B) Let $t_A = 2 \ s$ be the time interval for boy $A$ and $t_B = 1 \ s$ be the time interval for boy $B$.For a ball projected vertically, the time taken to reach the maximum height from a point at height $h$ is $t/2$.Using $v = u + at$, at the highest point $v = 0$, so $u = g(t/2)$.The height $h$ of the point from the ground is given by $h = u(t/2) - 1/2 g(t/2)^2 = g(t/2)^2 - 1/2 g(t/2)^2 = 1/2 g(t/2)^2 = 1/8 g t^2$.For boy $A$: $h_A = 1/8 \times 10 \times (2)^2 = 5 \ m$.For boy $B$: $h_B = 1/8 \times 10 \times (1)^2 = 1.25 \ m$.The difference in vertical positions is $h_A - h_B = 5 \ m - 1.25 \ m = 3.75 \ m$.

Class 11 Physics Motion in Straight Line Motion Under Gravity

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$A$ ball is projected vertically up from the ground. Boy $A$, standing at the window of the first floor of a nearby building, observes that the time interval between the ball crossing him while going up and the ball crossing him while going down is $2 \ s$. Another boy $B$, standing on the second floor, notices the time interval between the ball passing him twice, during up and down motion, is $1 \ s$. Calculate the difference between the vertical positions of boy $B$ and boy $A$. (Assume $g = 10 \ m \ s^{-2}$) (in $m$)

TS EAMCET 2019 All TS EAMCET

A
$8.45$
B
$3.75$
C
$4.25$
D
$2.50$

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Class 11

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Motion in Straight Line

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Motion Under Gravity

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$A$ body projected vertically upwards with a velocity $u$ returns to the starting point in $4 \, s$. If $g = 10 \, m/s^2$,the value of $u$ is $......... \, m/s$.

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$A$ ball is projected vertically upward with an initial velocity of $50 \; ms^{-1}$ at $t = 0 \; s$. At $t = 2 \; s$,another ball is projected vertically upward with the same velocity. At $t = \dots \; s$,the second ball will meet the first ball $(g = 10 \; ms^{-2})$.

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$A$ stone is dropped from a building of height $h$ and it reaches the ground after $t$ seconds. From the same building,if two stones are thrown (one upwards and one downwards) with the same velocity $u$ and they reach the earth's surface after $t_1$ and $t_2$ seconds respectively,then:

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$A$ ball is thrown vertically upwards with an initial velocity $u$ and reaches its maximum height in $5 \,s$. The ratio of the distance travelled by the ball in the $2^{nd}$ and $7^{th}$ second is (assume $g=10 \,m/s^2$):

MediumTS EAMCET 2020

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$A$ ball is thrown upward with speed $10 \, m/s$ from the top of a tower and reaches the ground with a speed $20 \, m/s$. The height of the tower is ......... $m$. (Take $g = 10 \, m/s^2$)

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$A$ body projected vertically upwards with a velocity $u$ returns to the starting point in $4 \, s$. If $g = 10 \, m/s^2$,the value of $u$ is $......... \, m/s$.

$A$ ball is projected vertically upward with an initial velocity of $50 \; ms^{-1}$ at $t = 0 \; s$. At $t = 2 \; s$,another ball is projected vertically upward with the same velocity. At $t = \dots \; s$,the second ball will meet the first ball $(g = 10 \; ms^{-2})$.

$A$ stone is dropped from a building of height $h$ and it reaches the ground after $t$ seconds. From the same building,if two stones are thrown (one upwards and one downwards) with the same velocity $u$ and they reach the earth's surface after $t_1$ and $t_2$ seconds respectively,then:

$A$ ball is thrown vertically upwards with an initial velocity $u$ and reaches its maximum height in $5 \,s$. The ratio of the distance travelled by the ball in the $2^{nd}$ and $7^{th}$ second is (assume $g=10 \,m/s^2$):

$A$ ball is thrown upward with speed $10 \, m/s$ from the top of a tower and reaches the ground with a speed $20 \, m/s$. The height of the tower is ......... $m$. (Take $g = 10 \, m/s^2$)

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