(B) Since the retardation is constant, the average velocity is given by:$v_{av} = \frac{u + v}{2} = \frac{2 + 0}{2} = 1 \,m/s$The frictional force $f$

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(B) Since the retardation is constant, the average velocity is given by:$v_{av} = \frac{u + v}{2} = \frac{2 + 0}{2} = 1 \,m/s$The frictional force $f$ is given by:$f = \mu N = \mu mg$Given:Coefficient of friction, $\mu = 0.3$Mass of body, $m = 500 \,g = 0.5 \,kg$Acceleration due to gravity, $g = 10 \,m/s^2$Substituting the values:$f = 0.3 \times 0.5 \times 10 = 1.5 \,N$The average power $P_{av}$ developed by the frictional force is:$P_{av} = f \times v_{av}$$P_{av} = 1.5 \,N \times 1 \,m/s = 1.5 \,W$Thus, the absolute value of the average power is $1.5 \,W$.

Class 11 Physics Newton's Laws of Motion and Friction Kinetic Friction and Motion on Rough Horizontal Surface

Easy

$A$ small body of mass $500 \,g$ moves on a rough horizontal surface before finally stopping. The initial velocity of the body is $2 \,m/s$ and the coefficient of friction is $0.3$. Find the absolute value of the average power developed by the frictional force during the time of motion. (Take $g = 10 \,m/s^2$) (in $\,W$)

TS EAMCET 2018 All TS EAMCET

A
$1$
B
$1.5$
C
$2$
D
$2.5$

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Class 11

Physics Questions

Chapter

Newton's Laws of Motion and Friction

Subtopic

Kinetic Friction and Motion on Rough Horizontal Surface

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An object of mass $1 \,kg$ moving on a horizontal surface with initial velocity $8 \,m/s$ comes to rest after $10 \,s$. If one wants to keep the object moving on the same surface with velocity $8 \,m/s$,the force required is ...... $N$.

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$A$ force $F$ pulls a block of mass $60 \ kg$ at a constant speed across the floor. The coefficient of friction is $\mu = 1/3$. What is the magnitude of the force $F$ (in $N$)?

$A$ block of mass $2 \,kg$ is being pushed against a wall by a force $F=90 \,N$ as shown in the figure. If the coefficient of friction is $0.25$, then the magnitude of acceleration of the block is (Take $g=10 \,ms^{-2}$, $\sin 37^{\circ}=\frac{3}{5}$). (in $\,ms^{-2}$)

If the normal reaction is $R$ and the coefficient of friction is $\mu$,what is the work done against friction in moving a body by a distance $d$ slowly?

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