[P] xrightarrow{Br_{2}} C_{2}H_{4}Br_{2} xrig | vedclass

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Question

(A) The given reaction sequence is:$1$. $[P]$ is ethene $(CH_{2}=CH_{2})$. Reaction with $Br_{2}$ gives $1,2-dibromoethane$ $(CH_{2}Br-CH_{2}Br)$.$2$.

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ethene, ethyne, ethanal, ethane

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(A) The given reaction sequence is:$1$. $[P]$ is ethene $(CH_{2}=CH_{2})$. Reaction with $Br_{2}$ gives $1,2-dibromoethane$ $(CH_{2}Br-CH_{2}Br)$.$2$. $1,2-dibromoethane$ reacts with $NaNH_{2}/NH_{3}$ (dehydrohalogenation) to form ethyne $(HC \equiv CH)$ as $[Q]$.$3$. Ethyne $[Q]$ reacts with $20 \% H_{2}SO_{4}$ and $Hg^{2+}$ (Kucherov reaction) to form ethanal $(CH_{3}CHO)$ as $[R]$.$4$. Ethanal $[R]$ undergoes Clemmensen reduction $(Zn-Hg/HCl)$ to form ethane $(CH_{3}CH_{3})$ as $[S]$.Thus, $[P]$ = ethene, $[Q]$ = ethyne, $[R]$ = ethanal, $[S]$ = ethane.

$[P]$ $\xrightarrow{Br_{2}} C_{2}H_{4}Br_{2}$ $\xrightarrow{NaNH_{2}/NH_{3}} [Q]$
$[Q]$ $\xrightarrow{20 \% H_{2}SO_{4}, Hg^{2+}, \Delta} [R]$ $\xrightarrow{Zn-Hg/HCl} [S]$
The species $[P], [Q], [R]$ and $[S]$ respectively are:

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$[P]$ $\xrightarrow{Br_{2}} C_{2}H_{4}Br_{2}$ $\xrightarrow{NaNH_{2}/NH_{3}} [Q]$$[Q]$ $\xrightarrow{20 \% H_{2}SO_{4}, Hg^{2+}, \Delta} [R]$ $\xrightarrow{Zn-Hg/HCl} [S]$The species $[P], [Q], [R]$ and $[S]$ respectively are: