A spherical ball A of mass 4 kg, moving alon | vedclass

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Question

(A) According to the law of conservation of linear momentum, the net external force on the system is zero, so the momentum along the $y$-axis (perpend

Vedclass · Accepted Answer

$\frac{\sqrt{3}}{4}$

Vedclass · Answer

(A) According to the law of conservation of linear momentum, the net external force on the system is zero, so the momentum along the $y$-axis (perpendicular to the initial direction of motion) must be conserved.Initially, the system has no momentum along the $y$-axis.After the collision, the components of momentum along the $y$-axis for balls $A$ and $B$ must be equal and opposite.Let $m_1 = 4 \ kg$ and $m_2 = 1 \ kg$.$m_1 v_1 \sin(30^{\circ}) = m_2 v_2 \sin(60^{\circ})$$4 \cdot v_1 \cdot \frac{1}{2} = 1 \cdot v_2 \cdot \frac{\sqrt{3}}{2}$$2 v_1 = \frac{\sqrt{3}}{2} v_2$$\frac{v_1}{v_2} = \frac{\sqrt{3}}{4}$

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