A homonuclear diatomic gas molecule shows 2-e | vedclass

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(C) The molecule is $O_2$. $1$. $O_2$ has two unpaired electrons in its antibonding $\pi^*{2p}$ orbitals, which corresponds to a $2$-electron magnetic

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$O_2$

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(C) The molecule is $O_2$. $1$. $O_2$ has two unpaired electrons in its antibonding $\pi^*{2p}$ orbitals, which corresponds to a $2$-electron magnetic moment (paramagnetic). $2$. The one-electron reduced species is the superoxide ion $(O_2^-)$ and the two-electron reduced species is the peroxide ion $(O_2^{2-})$. Both can act as oxidizing and reducing agents. $3$. When $O_2$ is one-electron oxidized, it forms the dioxygenyl cation $(O_2^+)$. In $O_2$, the bond order is $2.0$ (electrons in antibonding orbitals). Removing one electron from the antibonding orbital increases the bond order to $2.5$, which causes the bond length to decrease.

List-$I$ (Molecule / ion)	List-$II$ (Bond order)
$1$. $NO$	$i$. $1.5$
$2$. $CO$	$ii$. $2.0$
$3$. $O_2^{-}$	$iii$. $2.5$
$4$. $O_2$	$iv$. $3.0$

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Match List-$I$ with List-$II$ and select the correct option:
List-$I$ (Molecule / ion) List-$II$ (Bond order)
$1$. $NO$ $i$. $1.5$
$2$. $CO$ $ii$. $2.0$
$3$. $O_2^{-}$ $iii$. $2.5$
$4$. $O_2$ $iv$. $3.0$

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