A charge of 0.8 text{ C} is divided into two | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the total charge be $Q = 0.8 	ext{ C}$.Let $Q_{1} = q$, then $Q_{2} = Q - q = (0.8 - q)$.The electrostatic force between the two charges is g

Vedclass · Accepted Answer

$Q_{1} = Q_{2} = 0.4 	ext{ C}$

Vedclass · Answer

(A) Let the total charge be $Q = 0.8 	ext{ C}$.Let $Q_{1} = q$, then $Q_{2} = Q - q = (0.8 - q)$.The electrostatic force between the two charges is given by Coulomb's Law:$F = \frac{k Q_{1} Q_{2}}{r^{2}} = \frac{k q (0.8 - q)}{r^{2}}$For the force $F$ to be maximum, the derivative of $F$ with respect to $q$ must be zero:$\frac{dF}{dq} = \frac{k}{r^{2}} \frac{d}{dq} (0.8q - q^{2}) = 0$$0.8 - 2q = 0$$2q = 0.8$$q = 0.4 	ext{ C}$Thus, $Q_{1} = 0.4 	ext{ C}$ and $Q_{2} = 0.8 - 0.4 = 0.4 	ext{ C}$.Therefore, the force is maximum when $Q_{1} = Q_{2} = 0.4 	ext{ C}$.

$A$ charge of $0.8 \text{ C}$ is divided into two charges $Q_{1}$ and $Q_{2}$. These are kept at a separation of $30 \text{ cm}$. The force on $Q_{1}$ is maximum when

Similar Questions

$A$ charge of $4\,\mu C$ is to be divided into two parts. The distance between the two divided charges is constant. What should be the magnitude of the divided charges so that the electrostatic force between them is maximum?

Point charges $+4q, -q$ and $+4q$ are kept on the $x$-axis at points $x = 0, x = a$ and $x = 2a$ respectively. Then:

Two point charges $+9e$ and $+e$ are placed at a distance of $16\, cm$ from each other. Where should a third charge $q$ be placed between them so that the system remains in equilibrium?

Two point charges placed at a distance $r$ in air experience a certain force. Then the distance at which they will experience the same force in a medium of dielectric constant $K$ is

Two particles of equal mass $m$ and equal charge $q$ are separated by a distance of $16 \text{ cm}$. They do not experience any net force. The value of $\frac{q}{m}$ is . . . . . . (where $G$ is the universal gravitational constant and $\epsilon_0$ is the permittivity of free space).

Vedclass Test Series

Exam Paper Generator

Online Exam Module