A sample of MgCO_3 is dissolved in dil. HCl a | vedclass

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(B) The reaction proceeds as follows:$1$. $MgCO_3(s) + 2HCl(aq) \rightarrow MgCl_2(aq) + H_2O(l) + CO_2(g)$$2$. The solution is neutralized with ammon

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$Mg(NH_4)PO_4$

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(B) The reaction proceeds as follows:$1$. $MgCO_3(s) + 2HCl(aq) \rightarrow MgCl_2(aq) + H_2O(l) + CO_2(g)$$2$. The solution is neutralized with ammonia and buffered with $NH_4Cl / NH_4OH$.$3$. Upon adding disodium hydrogen phosphate $(Na_2HPO_4)$ to the solution containing $Mg^{2+}$ ions in the presence of $NH_4^+$ ions, a white crystalline precipitate of magnesium ammonium phosphate is formed:$Mg^{2+}(aq) + NH_4^+(aq) + HPO_4^{2-}(aq) \rightarrow Mg(NH_4)PO_4(s) \downarrow$Thus, the formula of the white precipitate is $Mg(NH_4)PO_4$.

$A$ sample of $MgCO_3$ is dissolved in dil. $HCl$ and the solution is neutralized with ammonia and buffered with $NH_4Cl / NH_4OH$. Disodium hydrogen phosphate reagent is added to the resulting solution. $A$ white precipitate is formed. What is the formula of the precipitate?

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