A compound formed by elements X and Y crystal | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The number of $X$ atoms at the corners of the cube is $8$. Since each corner atom contributes $\frac{1}{8}$ to the unit cell, the total number of

Vedclass · Accepted Answer

$XY$

Vedclass · Answer

(A) The number of $X$ atoms at the corners of the cube is $8$. Since each corner atom contributes $\frac{1}{8}$ to the unit cell, the total number of $X$ atoms per unit cell is $8 	imes \frac{1}{8} = 1$.The number of $Y$ atoms at the body centre is $1$. Since the body-centered atom is entirely within the unit cell, the total number of $Y$ atoms per unit cell is $1$.Therefore, the ratio of $X:Y$ is $1:1$, and the formula of the compound is $XY$.

$A$ compound formed by elements $X$ and $Y$ crystallises in a cubic structure, where $X$ atoms are at the corners of a cube and $Y$ atoms are at the body centre. The formula of the compound is:

Similar Questions

The number of carbon atoms per unit cell of diamond unit cell is

The number of close neighbours in a body-centred cubic $(BCC)$ lattice of identical spheres is:

In an end-centered unit cell,the body diagonal contains two additional atoms. What is the total number of atoms present in the unit cell?

In a face-centered cubic $(FCC)$ arrangement,atoms $A$ are present at the corners and atoms $B$ are present at the face centers. If $4$ atoms of $A$ are removed from the corners,what is the empirical formula of the compound?

Which statement is correct for the antifluorite structure of $Na_2O$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module