x is the product obtained from propanenitrile | vedclass

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(D) $1$. Propanenitrile $(CH_3CH_2CN)$ on reduction with $SnCl_2/HCl$ followed by hydrolysis gives propanal $(CH_3CH_2CHO)$, which is $x$.$2$. But$-2-

Vedclass · Accepted Answer

$3-$Methylbut$-2-$enal

Vedclass · Answer

(D) $1$. Propanenitrile $(CH_3CH_2CN)$ on reduction with $SnCl_2/HCl$ followed by hydrolysis gives propanal $(CH_3CH_2CHO)$, which is $x$.$2$. But$-2-$ene $(CH_3CH=CHCH_3)$ on ozonolysis followed by hydrolysis gives two moles of ethanal $(CH_3CHO)$, which is $y$.$3$. The reaction between propanal $(x)$ and ethanal $(y)$ in the presence of alkali $(NaOH)$ and heat is a crossed aldol condensation reaction.$4$. The possible products are:- Self-aldol of propanal: $CH_3CH_2CH(OH)CH(CH_3)CHO \xrightarrow{\Delta} CH_3CH_2CH=C(CH_3)CHO$ ($2-$Methylpent$-2-$enal).- Self-aldol of ethanal: $CH_3CH(OH)CH_2CHO \xrightarrow{\Delta} CH_3CH=CHCHO$ (But$-2-$enal).- Crossed-aldol ($CH_3CHO$ as nucleophile): $CH_3CH_2CH(OH)CH_2CHO \xrightarrow{\Delta} CH_3CH_2CH=CHCHO$ (Pent$-2-$enal).- Crossed-aldol ($CH_3CH_2CHO$ as nucleophile): $CH_3CH(OH)CH(CH_3)CHO \xrightarrow{\Delta} CH_3CH=C(CH_3)CHO$ ($2-$Methylbut$-2-$enal).$5$. $3-$Methylbut$-2-$enal is not formed in this reaction.

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