Difficult
$A$ student has been given $0.314 \ g$ of an organic compound and asked to estimate Sulphur. During the experiment, the student has obtained $0.4813 \ g$ of barium sulphate. The percentage of sulphur present in the compound is . . . . . .
(Given Molar mass in $g \ mol^{-1}$: $S = 32$, $BaSO_4 = 233$) (in $\%$)
(Given Molar mass in $g \ mol^{-1}$: $S = 32$, $BaSO_4 = 233$) (in $\%$)
- A$42.10$
- B$63.15$
- C$21.05$
- D$48.24$
Explore More
Similar Questions
In Kjeldahl's method for estimation of nitrogen,$CuSO_4$ acts as :
DifficultJEE MAIN 2024
View SolutionAn organic compound is subjected to chlorination to get compound $A$. When $0.5 \ g$ of compound $A$ is reacted with $AgNO_3$ [Carius Method],it forms $0.3849 \ g$ of $AgCl$. Calculate the percentage of chlorine in compound $A$. (Round off to the nearest integer)
(Atomic masses of $Ag$ and $Cl$ are $107.87$ and $35.5$ respectively)
(Atomic masses of $Ag$ and $Cl$ are $107.87$ and $35.5$ respectively)
DifficultJEE MAIN 2021
View SolutionExplain Quantitative Analysis.
Medium
View SolutionIn sulphur estimation,$0.471 \ g$ of an organic compound gave $1.4439 \ g$ of barium sulphate. The percentage of sulphur in the compound is $.............$ (Nearest Integer) (Given: Atomic mass $Ba: 137 \ u, S: 32 \ u, O: 16 \ u$)
DifficultJEE MAIN 2023
View SolutionThe transformation occurring in Dumas's method is given below:
$C_{2}H_{7}N + (2x + \frac{y}{2})CuO \rightarrow xCO_{2} + \frac{y}{2}H_{2}O + \frac{z}{2}N_{2} + (2x + \frac{y}{2})Cu$
The value of $y$ is ...... .(Integer answer)
$C_{2}H_{7}N + (2x + \frac{y}{2})CuO \rightarrow xCO_{2} + \frac{y}{2}H_{2}O + \frac{z}{2}N_{2} + (2x + \frac{y}{2})Cu$
The value of $y$ is ...... .(Integer answer)
DifficultJEE MAIN 2021
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo