A monoatomic anion (A^-) has 45 neutrons and | vedclass

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(A) $1$. The anion $A^-$ has $36$ electrons. Since it is a monoatomic anion with a $-1$ charge, the neutral atom $A$ must have $36 - 1 = 35$ electrons

Vedclass · Accepted Answer

$80, 17, 	ext{liquid}$

Vedclass · Answer

(A) $1$. The anion $A^-$ has $36$ electrons. Since it is a monoatomic anion with a $-1$ charge, the neutral atom $A$ must have $36 - 1 = 35$ electrons.
$2$. The atomic number $(Z)$ of the element is equal to the number of protons, which is $35$ for a neutral atom. This element is Bromine $(Br)$.
$3$. The mass number $(A_{mass})$ is the sum of protons and neutrons: $A_{mass} = Z + n = 35 + 45 = 80$.
$4$. Bromine belongs to Group $17$ (Halogens) of the periodic table.
$5$. Bromine is one of the few elements that exists as a liquid at room temperature.
$6$. Therefore, the atomic mass is $80$, the group is $17$, and the physical state is liquid.

$A$ monoatomic anion $(A^-)$ has $45$ neutrons and $36$ electrons. The atomic mass, group in the periodic table, and physical state at room temperature of the element $(A)$ are respectively:

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