A rod of length 10 text{ cm} lies along the p | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) For a concave mirror, the focal length $f = -10 	ext{ cm}$.The rod is placed from $u_1 = -20 	ext{ cm}$ to $u_2 = -30 	ext{ cm}$ (since the len

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(B) For a concave mirror, the focal length $f = -10 	ext{ cm}$.The rod is placed from $u_1 = -20 	ext{ cm}$ to $u_2 = -30 	ext{ cm}$ (since the length is $10 	ext{ cm}$ and the near end is at $20 	ext{ cm}$ from the pole).Using the mirror formula $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$:For the near end at $u_1 = -20 	ext{ cm}$:$\frac{1}{v_1} - \frac{1}{20} = -\frac{1}{10} \implies \frac{1}{v_1} = -\frac{1}{10} + \frac{1}{20} = -\frac{1}{20} \implies v_1 = -20 	ext{ cm}$.For the far end at $u_2 = -30 	ext{ cm}$:$\frac{1}{v_2} - \frac{1}{30} = -\frac{1}{10} \implies \frac{1}{v_2} = -\frac{1}{10} + \frac{1}{30} = -\frac{2}{30} = -\frac{1}{15} \implies v_2 = -15 	ext{ cm}$.The length of the image is the distance between the images of the two ends:$	ext{Length of image} = |v_1 - v_2| = |-20 - (-15)| = |-5| = 5 	ext{ cm}$.

$A$ rod of length $10 \text{ cm}$ lies along the principal axis of a concave mirror of focal length $10 \text{ cm}$ as shown in the figure. The length of the image is . . . . . . $\text{cm}$.

Similar Questions

An object $5 \ cm$ tall is placed $1 \ m$ from a concave spherical mirror which has a radius of curvature of $20 \ cm$. The size of the image is $...... \ cm$.

An object of height $3.6 \ cm$ is placed normally on the principal axis of a concave mirror of radius of curvature $30 \ cm$. If the object is at a distance of $10 \ cm$ from the principal focus of the mirror, then the height of the real image formed due to the mirror is (in $cm$)

If $x$ is the distance of an object from the focus of a concave mirror and $y$ is the distance of the image from the focus, then which of the following graphs is correct between $x$ and $y$?

An object $2.5 \, cm$ high is placed at a distance of $10 \, cm$ from a concave mirror of radius of curvature $30 \, cm$. The size of the image is ........ $cm$.

What will be the height of the image (in $mm$) when an object of $2 \, mm$ is placed on the axis of a convex mirror at a distance of $20 \, cm$,given the radius of curvature is $40 \, cm$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module