(A) The farthest distance reached by the bullets is the maximum horizontal range, denoted by $R_{max}$.The formula for the maximum horizontal range is

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(A) The farthest distance reached by the bullets is the maximum horizontal range, denoted by $R_{max}$.The formula for the maximum horizontal range is $R_{max} = \frac{u^2}{g}$, where $u$ is the initial speed and $g$ is the acceleration due to gravity.Given values are $R_{max} = 6.4 \text{ m}$ and $g = 10 \text{ m/s}^2$.Substituting these values into the formula: $6.4 = \frac{u^2}{10}$.Multiplying both sides by $10$, we get $u^2 = 64$.Taking the square root of both sides, we find $u = 8 \text{ m/s}$.

Class 11 Physics 3-2.Motion in Plane Horizontal Projectile Motion

Medium

$A$ gun mounted on the ground fires bullets in all directions with same speed. The farthest distance the bullets could reach is $6.4 \text{ m}$. The speed of the bullets from the gun is . . . . . . m/s. (take $g = 10 \text{ m/s}^2$)

JEE MAIN 2026 All JEE MAIN

A
$8$
B
$10$
C
$12$
D
$16$

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3-2.Motion in Plane

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Horizontal Projectile Motion

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In the given figure for a projectile,find the relation for $y$ in terms of $x_1, x_2$ and $\theta$.

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$A$ particle of mass $m$ is projected with a velocity $u$ making an angle of $30^{\circ}$ with the horizontal. The magnitude of the angular momentum of the projectile about the point of projection when the particle is at its maximum height $h$ is:

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$A$ cricketer can throw a ball to a maximum horizontal distance of $100\, m$. The speed with which he throws the ball is ......... $m/s$ (to the nearest integer).

MediumAIIMS 2019

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$A$ ball is projected with kinetic energy $E$ at an angle of $45^\circ$ to the horizontal. At the highest point during its flight,its kinetic energy will be

MediumAIPMT 2001

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$A$ gun mounted on the ground fires bullets in all directions with same speed. The farthest distance the bullets could reach is $6.4 \text{ m}$. The speed of the bullets from the gun is . . . . . . m/s. (take $g = 10 \text{ m/s}^2$)

Similar Questions

In the given figure for a projectile,find the relation for $y$ in terms of $x_1, x_2$ and $\theta$.

The maximum horizontal range of a projectile is $16 \ km$. When the projectile is thrown at an elevation of $30^o$ from the horizontal,it will reach a maximum height of ....... $km$.

$A$ particle of mass $m$ is projected with a velocity $u$ making an angle of $30^{\circ}$ with the horizontal. The magnitude of the angular momentum of the projectile about the point of projection when the particle is at its maximum height $h$ is:

$A$ cricketer can throw a ball to a maximum horizontal distance of $100\, m$. The speed with which he throws the ball is ......... $m/s$ (to the nearest integer).

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