$A$ bag contains $6$ blue and $6$ green balls. Pairs of balls are drawn without replacement until the bag is empty. The probability that each drawn pair consists of one blue and one green ball is:

  • A
    $\frac{63}{925}$
  • B
    $\frac{17}{231}$
  • C
    $\frac{16}{231}$
  • D
    $\frac{64}{925}$

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