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(D) When a spherical object falls through a viscous fluid, it experiences three forces: the gravitational force $(F_g)$ acting downwards, the buoyant

Vedclass · Accepted Answer

buoyant force plus viscous force becomes equal to force due to gravity.

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(D) When a spherical object falls through a viscous fluid, it experiences three forces: the gravitational force $(F_g)$ acting downwards, the buoyant force $(F_b)$ acting upwards, and the viscous drag force $(F_v)$ acting upwards.As the velocity of the sphere increases, the viscous force increases. Terminal velocity is reached when the net force on the sphere becomes zero, meaning the object stops accelerating.At this point, the downward force is balanced by the sum of the upward forces:$F_g = F_b + F_v$Therefore, the buoyant force plus the viscous force becomes equal to the force due to gravity.

$A$ spherical object is falling under gravity through a viscous fluid. The sphere attains the terminal velocity when

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