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(A) Let $Q$ be the total incident heat, $Q_r$ be the reflected heat, $Q_t$ be the transmitted heat, and $Q_a$ be the absorbed heat.According to the la

Vedclass · Accepted Answer

$(x-y)/x$

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(A) Let $Q$ be the total incident heat, $Q_r$ be the reflected heat, $Q_t$ be the transmitted heat, and $Q_a$ be the absorbed heat.According to the law of conservation of energy, the total incident heat is the sum of reflected, transmitted, and absorbed heat:$Q = Q_r + Q_t + Q_a$Given that $Q = x$ and the sum of reflected and transmitted heat is $Q_r + Q_t = y$.Substituting these values into the equation:$x = y + Q_a$$Q_a = x - y$The absorption coefficient $a$ is defined as the ratio of absorbed heat to the total incident heat:$a = Q_a / Q$$a = (x - y) / x$Therefore, the correct option is $(x - y) / x$.

$x$ joule of heat is incident on a body. Out of it, the total heat reflected and transmitted by it is $y$ joule. The absorption coefficient of the body is

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