A spring executes S.H.M. with mass 10 text{ k | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given:Mass $m = 10 	ext{ kg}$Force constant $k = 10 	ext{ N/m}$Velocity $v = 40 	ext{ cm/s} = 0.4 	ext{ m/s}$Amplitude $A = 0.5 	ext{ m}$Angu

Vedclass · Accepted Answer

$0.3$

Vedclass · Answer

(B) Given:Mass $m = 10 	ext{ kg}$Force constant $k = 10 	ext{ N/m}$Velocity $v = 40 	ext{ cm/s} = 0.4 	ext{ m/s}$Amplitude $A = 0.5 	ext{ m}$Angular frequency $\omega = \sqrt{\frac{k}{m}} = \sqrt{\frac{10}{10}} = 1 	ext{ rad/s}$.The velocity of a particle in $S$.$H$.$M$. is given by $v = \omega \sqrt{A^2 - x^2}$, where $x$ is the displacement.Substituting the values: $0.4 = 1 	imes \sqrt{(0.5)^2 - x^2}$.Squaring both sides: $(0.4)^2 = (0.5)^2 - x^2$.$0.16 = 0.25 - x^2$.$x^2 = 0.25 - 0.16 = 0.09$.$x = \sqrt{0.09} = 0.3 	ext{ m}$.Thus, the displacement is $0.3 	ext{ m}$.

$A$ spring executes $S$.$H$.$M$. with mass $10 \text{ kg}$ attached to it. The force constant of spring is $10 \text{ N/m}$. If at any instant its velocity is $40 \text{ cm/s}$, the displacement at that instant is (Amplitude of $S$.$H$.$M$. is $0.5 \text{ m}$) (in $\text{ m}$)

Similar Questions

$A$ spring executes $S.H.M.$ with a mass of $1 \,kg$ attached to it. The force constant of the spring is $4 \,N/m$. If at any instant its velocity is $20 \,cm/s$, the displacement at that instant is (Amplitude of $S.H.M.$ is $0.4 \,m$)

The maximum velocity of a particle performing $S.H.M.$ is $V$. If the periodic time is made $\left(\frac{1}{3}\right)^{rd}$ of its original value and the amplitude is doubled,then the new maximum velocity of the particle will be:

The amplitude of a particle executing $SHM$ is $4 \,cm$. At the mean position,the speed of the particle is $16 \,cm/s$. The distance of the particle from the mean position at which the speed of the particle becomes $8\sqrt{3} \,cm/s$ will be .... $cm$.

The plot of velocity $(v)$ versus displacement $(x)$ of a particle executing simple harmonic motion is shown in the figure. The time period of oscillation of the particle is .........

The displacement of a particle in $S.H.M.$ is given by $x = A \cos(\omega t + \pi/6)$. At what time will its speed be maximum?

Vedclass Test Series

Exam Paper Generator

Online Exam Module