A conducting loop of radius 10/sqrt{pi} cm is | vedclass

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(B) The radius of the loop is $r = 10/\sqrt{\pi}$ $cm = 0.1/\sqrt{\pi}$ $m$.The area of the loop is $A = \pi r^2 = \pi 	imes (0.1/\sqrt{\pi})^2 = \pi

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$10$

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(B) The radius of the loop is $r = 10/\sqrt{\pi}$ $cm = 0.1/\sqrt{\pi}$ $m$.The area of the loop is $A = \pi r^2 = \pi 	imes (0.1/\sqrt{\pi})^2 = \pi 	imes (0.01/\pi) = 0.01$ $m^2$.The magnetic field $B$ changes from $0.5$ $T$ to $0$ $T$ in a time interval $\Delta t = 0.5$ $s$.The rate of change of the magnetic field is $\frac{dB}{dt} = \frac{|0 - 0.5|}{0.5} = 1$ $T/s$.According to Faraday's law of induction, the induced emf $\varepsilon$ is given by $\varepsilon = A \frac{dB}{dt}$.Substituting the values, $\varepsilon = 0.01 	imes 1 = 0.01$ $V$.Since $1$ $V = 1000$ $mV$, the induced emf is $0.01 	imes 1000 = 10$ $mV$.

$A$ conducting loop of radius $10/\sqrt{\pi}$ $cm$ is placed perpendicular to a uniform magnetic field of $0.5$ $T$. The magnetic field is decreased to zero in $0.5$ $s$ at a steady rate. The induced emf in the circular loop at $0.25$ $s$ is (in $mV$)

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