(A) Given: Source voltage $V = 100 \text{ V}$, Inductive reactance $X_L = 24 \text{ } \Omega$, Capacitive reactance $X_C = 16 \text{ } \Omega$, Resist

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(A) Given: Source voltage $V = 100 \text{ V}$, Inductive reactance $X_L = 24 \text{ } \Omega$, Capacitive reactance $X_C = 16 \text{ } \Omega$, Resistance $R = 6 \text{ } \Omega$. First, calculate the impedance $Z$ of the $LCR$ circuit: $Z = \sqrt{R^2 + (X_L - X_C)^2} = \sqrt{6^2 + (24 - 16)^2} = \sqrt{36 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10 \text{ } \Omega$. The current $I$ in the circuit is $I = V / Z = 100 / 10 = 10 \text{ A}$. The potential difference across the series combination of inductor and capacitor is $V_{LC} = I |X_L - X_C|$. $V_{LC} = 10 \times |24 - 16| = 10 \times 8 = 80 \text{ V}$.

Class 12 Physics Alternating Current RL, RC and LC AC Circuits

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$A$ series $LCR$ circuit containing an $a.c.$ source of $100 \text{ V}$ has an inductor and a capacitor of reactance $24 \text{ } \Omega$ and $16 \text{ } \Omega$ respectively. If a resistance of $6 \text{ } \Omega$ is connected in series, then the potential difference across the series combination of inductor and capacitor only is: (in $\text{ V}$)

MHT CET 2026 All MHT CET

A
$80$
B
$8$
C
$40$
D
$20$

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RL, RC and LC AC Circuits

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