A simple microscope is used to see an object | vedclass

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(A) The magnifying power $(M)$ of a simple microscope is given by the formula $M = 1 + \frac{D}{f}$, where $D$ is the least distance of distinct visio

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decreases

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(A) The magnifying power $(M)$ of a simple microscope is given by the formula $M = 1 + \frac{D}{f}$, where $D$ is the least distance of distinct vision and $f$ is the focal length of the convex lens.According to Cauchy's equation, the refractive index $(\mu)$ of a material depends on the wavelength $(\lambda)$ of light as $\mu = A + \frac{B}{\lambda^2}$.Since the wavelength of red light $(\lambda_R)$ is greater than the wavelength of blue light $(\lambda_B)$, the refractive index for red light $(\mu_R)$ is less than that for blue light $(\mu_B)$.The focal length $(f)$ of a lens is related to the refractive index by the lens maker's formula: $\frac{1}{f} = (\mu - 1) (\frac{1}{R_1} - \frac{1}{R_2})$.Since $\mu_R From the formula $M = 1 + \frac{D}{f}$, we see that $M$ is inversely proportional to $f$.Therefore, as the light changes from blue to red, the focal length increases, which causes the magnifying power to decrease.

$A$ simple microscope is used to see an object first in blue light and then in red light. Due to the change from blue to red light, what is the effect on its magnifying power?

Similar Questions

Maximum magnification produced by a simple microscope of focal length $f=5 \,cm$ is

Which of the following statements are true in the context of a Compound Microscope?

$A$ compound microscope has a magnifying power of $30$. The focal length of its eyepiece is $5 \, cm$. Assuming the final image is formed at the least distance of distinct vision,the magnification produced by the objective is:

The near vision of an average person is $25 \, cm$. To view an object with an angular magnification of $10$,what should be the power of the microscope?

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