R - CH_2OH is converted into R - CHO by react | vedclass

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(D) $1$. $R - CH_2OH$ is a primary alcohol.$2$. Alkaline $KMnO_4$ is a strong oxidizing agent that oxidizes primary alcohols directly to carboxylic ac

Vedclass · Accepted Answer

$PCC$ (Pyridinium Chlorochromate)

Vedclass · Answer

(D) $1$. $R - CH_2OH$ is a primary alcohol.$2$. Alkaline $KMnO_4$ is a strong oxidizing agent that oxidizes primary alcohols directly to carboxylic acids.$3$. $LiAlH_4$ and $Na/C_2H_5OH$ are reducing agents.$4$. $PCC$ (Pyridinium Chlorochromate) is a mild oxidizing agent that selectively oxidizes primary alcohols to aldehydes without further oxidation to carboxylic acids.

$R - CH_2OH$ is converted into $R - CHO$ by reacting with . . . . . .

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