A source of frequency nu gives 6 text{ beats/ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Step $1$: From the first condition, the beat frequency is $|
u - 200| = 6$. This implies $
u = 200 \pm 6$, so $
u = 206 	ext{ Hz}$ or $
u = 1

Vedclass · Accepted Answer

$206$

Vedclass · Answer

(B) Step $1$: From the first condition, the beat frequency is $|
u - 200| = 6$. This implies $
u = 200 \pm 6$, so $
u = 206 	ext{ Hz}$ or $
u = 194 	ext{ Hz}$.Step $2$: From the second condition, the beat frequency for the second harmonic $2
u$ is $|2
u - 420| = 8$. This implies $2
u = 420 \pm 8$, so $2
u = 428 	ext{ Hz}$ or $2
u = 412 	ext{ Hz}$.Step $3$: Solving for $
u$ in the second condition gives $
u = 214 	ext{ Hz}$ or $
u = 206 	ext{ Hz}$.Step $4$: Comparing the results from both conditions, the common value is $
u = 206 	ext{ Hz}$.

$A$ source of frequency $\nu$ gives $6 \text{ beats/second}$ when sounded with a source of frequency $200 \text{ Hz}$. The second harmonic of frequency $2\nu$ of the source gives $8 \text{ beats/second}$ when sounded with a source of frequency $420 \text{ Hz}$. The value of $\nu$ is (in $text{ Hz}$)

Similar Questions

Beats are the result of

Two tuning forks of frequencies $320 \,Hz$ and $480 \,Hz$ are sounded together to produce sound waves. The velocity of sound in air is $320 \,ms^{-1}$. The difference between the wavelengths of these waves is nearly: (in $cm$)

$A$ set of $14$ tuning forks is arranged in a series of increasing frequencies. Each fork produces '$x$' beats per second with the preceding fork and the last fork is an octave of the first fork. If the seventh fork has the frequency of $114 \text{ Hz}$, the value of $x$ is

$56$ tuning forks are arranged such that each fork produces $4$ beats per second with its previous one. If the frequency of the last fork is twice that of the first, the frequency of the $19^{\text{th}}$ fork is . . . . . . (in $\text{Hz}$)

Three sound waves of equal amplitudes have frequencies $(n - 1)$,$n$,and $(n + 1)$. They superimpose to produce beats. The number of beats produced per second is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module